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Question

Physics Question on Conductivity-thermal and electrical

The temperature distribution along a fin with insulated tip is: w

A

θθx=e−mx\frac{\theta}{\theta_x}=e^{-mx}

B

θθx=emx\frac{\theta}{\theta_x}=e^{mx}

C

θθx=cosh m(l-x)cosh ml\frac{\theta}{\theta_x}=\frac{cosh\text{ m(l-x)}}{cosh\text{ ml}}

D

θθx=tanh m(l-x) ml\frac{\theta}{\theta_x}=\frac{tanh\text{ m(l-x)}}{\text{ ml}}

Answer

θθx=cosh m(l-x)cosh ml\frac{\theta}{\theta_x}=\frac{cosh\text{ m(l-x)}}{cosh\text{ ml}}

Explanation

Solution

The correct option is (C): θθx=cosh m(l-x)cosh ml\frac{\theta}{\theta_x}=\frac{cosh\text{ m(l-x)}}{cosh\text{ ml}}