Question

The temperature dependence of the rate constant k is expressed as $k = Ae^{- E_{a}/RT}$

When a plot between log k and $1/T$is plotted we get the graph as shown .

What is the value of slope in the graph?

• A. $\frac{E_{a}}{RT}$
• B. $- \frac{E_{a}}{2.303R}$
• C. $- \frac{E_{a}}{2.303RT}\log A$
• D. $- \frac{E_{a}}{2.303}\frac{R}{T}$

Answer 1

Answer: (B)

$- \frac{E_{a}}{2.303R}$

Answer 2

$\log k = \log A - \frac{E_{a}}{2.303R}\frac{1}{T}$

$\log k = - \frac{E_{a}}{2.303RT} + \log A$

$Slope = - \frac{E_{a}}{2.303R}$