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Question

Physics Question on Current electricity

The temperature coefficient of resistance ot a wire is 0.00125perC0.00125 \, per \, ^\circ C. At 300 K temperature its resistance is 1?1?. The resistance of the wire will be 2?2? at

A

1154 K

B

1100 K

C

1400 K

D

1127 K

Answer

1127 K

Explanation

Solution

R1R2=1+αt11+αt2\frac {R_1}{R_2}=\frac {1+\alpha t_1}{1+\alpha t_2} \Rightarrow \hspace30mm 12=(1+0.00125×27)(1+0.00125×t)\frac {1}{2}=\frac {(1+0.00125 \times 27)}{(1+0.00125 \times t)} \Rightarrow \hspace30mm t=854Ct={854}^\circ C \Rightarrow \hspace30mm T=1127K