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Question

Physics Question on Resistance

The temperature coefficient of resistance of a wire is 0.00125/K0.00125/K. At 300K300\,K its resistance is 1 Ω\Omega .The resistance of the wire will be 2 Ω\Omega at

A

1154 K

B

1100 K

C

1400 K

D

1127 K

Answer

1400 K

Explanation

Solution

The resistance RtR_{t} of a metal conductor at temperature tCt^{\circ} C is given by Rt=R0(1+αt+βt2)R_{t}=R_{0}\left(1+\alpha t+\beta t^{2}\right) where α\alpha and β\beta are temperature coefficients of resistance. R0R_{0} is the resistance of conductor at 0C0^{\circ} C. Their values vary from metal to metal. If the temperature tCt^{\circ} C is not sufficiently large which is so in the most practical cases, the above relation may be expressed as Rt=R0(1+αt)....R_{t} =R_{0}(1+\alpha t)....(i) Given, α=0.00125/K\alpha =0.00125 / K R300=1ΩR_{300}=1 \Omega From E (i), we have 1=R0(1+0.00125×300)1 =R_{0}(1+0.00125 \times 300)...(ii) and, 2=R0(1+0.00125×T)2 =R_{0}(1+0.00125 \times T) ...(iii) 21=1+0.00125×T1+0.00125×300\therefore \frac{2}{1} =\frac{1+0.00125 \times T}{1+0.00125 \times 300} or 2.75=1+0.00125×T2.75 =1+0.00125 \times T or T=1.750.00125T=\frac{1.75}{0.00125} =1400K=1400\, K