Question

The temperature co-efficient of resistance of a wire is 0.00125*/*⁰C. At 300 K. It’s resistance is 1Ω. The resistance of the wire will be 2Ω at

• A. 1154 K
• B. 1127 K
• C. 600 K
• D. 1400 K

Answer 1

Answer: (B)

1127 K

Answer 2

By using R_t = R_o (1 + α∆t) ⇒ $\frac{R_{1}}{R_{2}} = \frac{1 + \alpha t_{1}}{1 + \alpha t_{2}}$

So $\frac{1}{2} = \frac{1 + (300 - 273)\alpha}{1 + \alpha t_{2}}$ ⇒ t₂ = 854^oC = 1127 K