Question
Question: The temperature at which the velocity of oxygen will be half that of hydrogen at NTP is A. \(899\,...
The temperature at which the velocity of oxygen will be half that of hydrogen at NTP is
A. 899∘C
B.1492∘C
C.273K
D. 819∘C
Solution
Root mean square (RMS) velocity of the gas is directly proportional to the square root of the absolute temperature.
Complete Step by step answer:
From kinetic theory of gases, the pressure exerted by one mole of an ideal gas is P=31ρvrms2
We know density ρ=VM therefore the above equation become P=31VMvrms2
Therefore equation becomes PV=31Mvrms2
But according to ideal gas equation,PV=RT
Thus RMS velocity of the gas is given by,
Vrms=M3RT
Here R is the universal gas constant, T is the absolute temperature and M is the molar mass of the gas.
Let the velocity of hydrogen is V2 at NTP.
At NTP, the temperature of the hydrogen is T2=20∘C = 293K .
Molar mass of hydrogen is M2=2g.
Hence the velocity of hydrogen is, V1=0.5V2.
Let the temperature of the hydrogen is T1.
Molar mass of oxygen is M1=32g.
Since Vrms is directly proportional to MT.Hence,
V2V1=T2T1×M1M2
Hence, substituting the values of V1=0.5V2, T2=293K, M1=32g and M2=2g, it comes out to be.
V20.5V2=32×2932T1 T1=1172K T1=899∘C
Therefore, the correct option is (A).
Note:
- The square root of the sum of the squares of the velocities of all the gases divided by the total number of values is the root mean square velocity. Rates of effusion and diffusion are determined by the RMS velocity.
- The RMS velocity is taken into account to overcome the directional component of velocity.