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Question: The temperature at which a black body of unit area loses its energy at the rate of 1 joule/second is...

The temperature at which a black body of unit area loses its energy at the rate of 1 joule/second is

A

−65∘C- 65 ^ { \circ } C

B

65∘C65 ^ { \circ } \mathrm { C }

C

65 K

D

None of these

Answer

65 K

Explanation

Solution

5.6×10−8×T4=15.6 \times 10 ^ { - 8 } \times T ^ { 4 } = 1

⇒T=[15.6×10−8]1/4T = \left[ \frac { 1 } { 5.6 \times 10 ^ { - 8 } } \right] ^ { 1 / 4 }=65 K