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Question: The tangents drawn from the origin to the circle x<sup>2</sup>+y<sup>2</sup>-2rx-2hy+h<sup>2</sup> ...

The tangents drawn from the origin to the circle

x2+y2-2rx-2hy+h2 = 0 are perpendicular if

A

h = ± 2r

B

h = ± r

C

r2+h2 = 1

D

None

Answer

h = ± r

Explanation

Solution

The combined equation of the tangents drawn from (0,0) to x2+y2–2rx-2 hy + h2 = 0 is

(x2+y2 – 2 rx-2 hy + h2)h2 = (-rx – hy + h2)2.

This equation represents a pair of perpendicular straight lines if the coefficient of x2 + coefficient of y2 = 0

i.e. 2h2 – r2 – h2 = 0 ⇒ r2 = h2 or r = ± h