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Question: The tangent to the curve y = 2x<sup>2</sup> – x + 1 is parallel to the line y = 3x + 9 at the point ...

The tangent to the curve y = 2x2 – x + 1 is parallel to the line y = 3x + 9 at the point whose co-ordinates are :

A

(–1, 5)

B

(1, 2)

C

(2, 7)

D

(3, 16)

Answer

(1, 2)

Explanation

Solution

y = 2x2 –x + 1

dydx\frac{dy}{dx}= 4x –1 = 3 Ž x = 1