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Question: The tangent at the point P(x<sub>1</sub>, y<sub>1</sub>) to the parabola y<sup>2</sup> = 4ax meets t...

The tangent at the point P(x1, y1) to the parabola y2 = 4ax meets the parabola y2 = 4a(x + b) at Q and R, the coordinates of the mid-point of QR are

A

(x1 – a, y1 + b)

B

(x1, y1)

C

(x1 + b, y1 + a)

D

(x1 – b, y1 – b)

Answer

(x1, y1)

Explanation

Solution

Equation of the tangents at P(x1, y1) to the parabola

y2 = 4ax is yy1 = 2a(x + x1)

or 2ax – y1y + 2ax1 = 0 ….(i)

If M(h, k) is the mid-point of QR, then equation of QR a chord of the parabola y2 = 4a(x + b) in term of its mid-point is ky – 2a (x + h) – 4ab

= k2 – 4a (h + b) (using T = S ¢ )

or 2ax – ky + k2 – 2ah = 0 …...(ii)

Since (i) and (ii) represent the same line, we have

2a2a\frac{2a}{2a} = y1k\frac{y_{1}}{k} = 2ax1k22ah\frac{2ax_{1}}{k^{2} - 2ah}

̃ k = y1 and k2 – 2ah = 2ax1

̃ y12y_{1}^{2} – 2ah = 2ax1 ̃ 4ax1 – 2ax1 = 2ah

̃ h = x1