Question
Question: The tangent at the point P(x<sub>1</sub>, y<sub>1</sub>) to the parabola y<sup>2</sup> = 4ax meets t...
The tangent at the point P(x1, y1) to the parabola y2 = 4ax meets the parabola y2 = 4a(x + b) at Q and R, the coordinates of the mid-point of QR are
A
(x1 – a, y1 + b)
B
(x1, y1)
C
(x1 + b, y1 + a)
D
(x1 – b, y1 – b)
Answer
(x1, y1)
Explanation
Solution
Equation of the tangents at P(x1, y1) to the parabola
y2 = 4ax is yy1 = 2a(x + x1)
or 2ax – y1y + 2ax1 = 0 ….(i)
If M(h, k) is the mid-point of QR, then equation of QR a chord of the parabola y2 = 4a(x + b) in term of its mid-point is ky – 2a (x + h) – 4ab
= k2 – 4a (h + b) (using T = S ¢ )
or 2ax – ky + k2 – 2ah = 0 …...(ii)
Since (i) and (ii) represent the same line, we have
2a2a = ky1 = k2−2ah2ax1
̃ k = y1 and k2 – 2ah = 2ax1
̃ y12 – 2ah = 2ax1 ̃ 4ax1 – 2ax1 = 2ah
̃ h = x1