Question

The system of equations $2x + 3y = 7\:\: , 14x + 21y = 49$ has

• A. infinitely many solutions
• B. a unique solution
• C. no solution
• D. finitely many solutions

Answer 1

Answer: (A)

infinitely many solutions

Answer 2

Let A = $\begin{bmatrix}2&3\\\ 14&21\end{bmatrix}$ , det A = 0 Clearly, the given system has infinitely many solutions. $\because$ $7(2x +3y) = 7 \times 7$ given $14x + 21 y = 49$