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Question: The surface tension of soap solution is\(0.03Nm^{- 1}\) The work done in blowing to form a soap bubb...

The surface tension of soap solution is0.03Nm−10.03Nm^{- 1} The work done in blowing to form a soap bubble of surface area 40 cm2cm^{2} is

A

2.4×10−4 J2.4 \times 10^{- 4}\text{ J}

B

1.2×10−2 J1.2 \times 10^{- 2}\text{ J}

C

3.6×10−4 J3.6 \times 10^{- 4}\text{ J}

D

4.2×10−2 J4.2 \times 10^{- 2}\text{ J}

Answer

2.4×10−4 J2.4 \times 10^{- 4}\text{ J}

Explanation

Solution

Here surfaces tension S=0.03Nm−1S = 0.03Nm^{- 1}

Surface area =40cm2=40×10−4m2= 40cm^{2} = 40 \times 10^{- 4}m^{2}

Work done = surface tension × change in surface area =0.03×2×(40×10−4)J= 0.03 \times 2 \times (40 \times 10^{- 4})J =2.4×10−4J= 2.4 \times 10^{- 4}J