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Question: The surface tension of soap solution is \(25 \times 10 ^ { - 3 } \mathrm { Nm } ^ { - 1 }\). The exc...

The surface tension of soap solution is 25×10−3Nm−125 \times 10 ^ { - 3 } \mathrm { Nm } ^ { - 1 }. The excess pressure inside a soap bubble of diameter 1 cm is

A

10 Pa

B

20 Pa

C

5 Pa

D

None of the above

Answer

20 Pa

Explanation

Solution

Excess pressureΔP=4Tr\Delta P = \frac { 4 T } { r }

=4×2×25×10−31×10−2= \frac { 4 \times 2 \times 25 \times 10 ^ { - 3 } } { 1 \times 10 ^ { - 2 } } =20 N/m2=20 Pa= 20 \mathrm {~N} / \mathrm { m } ^ { 2 } = 20 \mathrm {~Pa}