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Physics Question on Surface tension

The surface tension of soap solution is 0.03 N/m0.03\, N/m. The work done in blowing to form a soap bubble of surface area 40 cm2,(in J)40 \, cm^2, (in\, J) is

A

1.2×10−41.2 \times 10^{-4}

B

2.4×10−42.4 \times 10^{-4}

C

12×10−412 \times 10^{-4}

D

24×10−424 \times 10^{-4}

Answer

2.4×10−42.4 \times 10^{-4}

Explanation

Solution

In case of soap bubble
W=T×2×ΔAW = T \times 2 \times \Delta A
=0.03×2×40×10−4= 0.03 \times 2 \times 40 \times 10^{-4}
=2.4×10−4 J= 2.4 \times 10^{-4} \, J