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Question

Question: The surface tension of liquid is 0.5 N/m. If a film is held on a ring of area 0.02 m<sup>2</sup>, it...

The surface tension of liquid is 0.5 N/m. If a film is held on a ring of area 0.02 m2, its surface energy is

A

5 × 10-2 joule

B

2.0 × 10-2 joule

C

4 × 10-4 joule

D

0.8 × 10-1 joule

Answer

2.0 × 10-2 joule

Explanation

Solution

Surface energy =T×ΔA=0.5×2×(0.02)T \times \Delta A = 0.5 \times 2 \times ( 0.02 )

=