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Question

Physics Question on Electric charges and fields

The surface charge density (in Cm−2Cm^{-2} ) of the earth is about

A

10−910^{-9}

B

−10−9-10^{-9}

C

10−910^{-9}

D

−10−9 -10^{-9}

Answer

−10−9 -10^{-9}

Explanation

Solution

Charge on the earth =−0.5×106C=-0.5 \times 10^{6} C
Charge density = charge  area =\frac{\text { charge }}{\text { area }}
Charge density =0.5×1064π×(6400×103)2=\frac{0.5 \times 10^{6}}{4 \pi \times\left(6400 \times 10^{3}\right)^{2}}
=−10−9Cm−2=-10^{-9} Cm ^{-2}