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Question: The sun’s angular diameter is measured to be 1920’’. The distance of the sun from the earth is \(1.4...

The sun’s angular diameter is measured to be 1920’’. The distance of the sun from the earth is 1.496×10111.496 \times 10^{11}m. What is the diameter of the sun?

A

1.39×109m1.39 \times 10^{9}m

B

1.39×1010m1.39 \times 10^{10}m

C

1.39×1011m1.39 \times 10^{11}m

D

1.39×1012m1.39 \times 10^{12}m

Answer

1.39×109m1.39 \times 10^{9}m

Explanation

Solution

Here,

Distance of the sun from the earth, d = 1.496×10111.496 \times 10^{11}m Sun’s angular diameter, α=1920\alpha = 1920''

1=4.85×106rad\because 1'' = 4.85 \times 10^{- 6}rad

α=1920×4.85×106rad\therefore\alpha = 1920'' \times 4.85 \times 10^{- 6}rad

=9.31×103rad= 9.31 \times 10^{- 3}rad

Sun’s diameter, D = αd\alpha d

D=(9.31×103)(1.496×1011)mD = (9.31 \times 10^{- 3})(1.496 \times 10^{11})m

=1.39×109m= 1.39 \times 10^{9}m