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Question

Physics Question on Units and measurement

The suns angular diameter is measured to be 19201920". The distance of the sun from the earth is 1.496×1011m1.496 \times 10^{11}\, m. What is the diameter of the sun ?

A

1.39×109m1.39 \times 10^9\,m

B

1.39×1010m1.39 \times 10^{10}\,m

C

1.39×1011m1.39 \times 10^{11}\,m

D

1.39×1012m1.39 \times 10^{12}\,m

Answer

1.39×109m1.39 \times 10^9\,m

Explanation

Solution

Here, Distance of the sun from the earth, d=1.496×1011md = 1.496 \times 10^{11}\, m Suns angular diameter, α=192\alpha = 192'' 1=4.85×106rad\because 1''=4.85 \times 10^{-6}\,rad α=1920×4.85×106rad\therefore \alpha = 1920 \times 4.85 \times 10^{-6}\,rad =9.31×106rad=9.31 \times 10^{-6}\,rad Suns diameter, D=αdD = \alpha d D=(9.31×103)(1.496×1011)mD=\left(9.31 \times 10^{-3}\right)\left(1.496 \times 10^{11}\right)m =1.39×109m=1.39 \times10^{9}\,m