Question
Question: The sum \(\sum_{i = 0}^{m}{\begin{pmatrix} 10 \\ i \end{pmatrix}\begin{pmatrix} 20 \\ m - i \end{pma...
The sum ∑i=0m(10i)(20m−i),(Where(pq)=0ifp<q), is
maximum when m is
A
5
B
15
C
10
D
20
Answer
20
Explanation
Solution
For m = 5, ∑i=05(10i)(205−i)
= (100)(205)+(101)(204)+......+(105)(200),
For m = 10, ∑i=010(10i)(2010−i)
= (100)(2010)+(101)(209)+(102)(208)......+(1010)(200),
For m = 15, ∑i=015(10i)(2015−i)
= (100)(2015)+(101)(2014)+(102)(2013)......+(1010)(205)
and for m = 20, ∑i=020(10i)(2020−i)
= (100)(2020)+(101)(2019)+.....+(1010)(2010)
Clearly, the sum is maximum for m = 15.
Note that 10Cr is maximum for r = 5 and 20Cr is maximum for r = 10. Note that the single term 10C5 x 20C10 (in case m = 15) is greater than the sum 10C0 20C2 + 10C9 20C1 + 10C10 20C0 (in case m = 10).
Also the sum incase m = 10 is same as that in case m = 20.