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Question

Question: The sum of the series\(\frac{1}{2.3} + \frac{1}{4.5} + \frac{1}{6.7} + ... =\)...

The sum of the series12.3+14.5+16.7+...=\frac{1}{2.3} + \frac{1}{4.5} + \frac{1}{6.7} + ... =

A

log(2/e)\log(2/e)

B

log(e/2)\log(e/2)

C

2/e

D

e/2

Answer

log(e/2)\log(e/2)

Explanation

Solution

(ex1)2(e^{x} - 1)^{2}

x4x^{4}

1+232!+333!+434!+....1 + \frac{2^{3}}{2!} + \frac{3^{3}}{3!} + \frac{4^{3}}{4!} + ....\infty.