The sum of the series (S = \frac{1}{19! } + \frac{1}{3!7!} +... | Mathematics | SolveeIt | Solveeit

Today, August 23

Question

The sum of the series $S = \frac{1}{19! } + \frac{1}{3!7!} + \frac{1}{5! 5!} + ...$ to 10 terms is equal to :

A

$\frac{2^{20}}{20!}$

B

$\frac{2^{10}}{20!}$

C

$\frac{2^{19}}{19!}$

D

$\frac{2^{19}}{20!}$

Answer

$\frac{2^{10}}{20!}$

Explanation

Solution

Answer (b) $\frac{2^{10}}{20!}$