Question

The sum of the numbers between 100 and 1000 which is divisible by 9 will be.

• A. 55350
• B. 57228
• C. 97015
• D. 62140

Answer 1

Answer: (A)

55350

Answer 2

Series is an A.P. where $a = 108$ , common difference $d = 9$ ,

$n = \frac { 999 } { 9 } - \frac { 99 } { 9 } = 111 - 11 = 100$

Hence required sum

= $\frac { 100 } { 2 } ( 108 + 999 ) = 50 \times 1107 = 55350$ .