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Question: The sum of the intercepts made by a tangent to the curve \(\sqrt{x}\) +\(\sqrt{y}\) = 4 at point (4...

The sum of the intercepts made by a tangent to the curve

x\sqrt{x} +y\sqrt{y} = 4 at point (4, 4) pm coordinate axes is –

A

42\sqrt{2}

B

33\sqrt{3}

C

82\sqrt{2}

D

256\sqrt{256}

Answer

256\sqrt{256}

Explanation

Solution

Let xn + yn = an at (x1, y1), then tangent is

xx11n\frac{x}{x_{1}^{1 - n}} + yy11n\frac{y}{y_{1}^{1 - n}} = an

Intercepts are x11–n. an and y11–n . an