Question

The sum of the focal distance of any point on the ellipse

4x² + y² = 16 is-

• A. 2
• B. 4
• C. 8
• D. 16

Answer 1

Answer: (C)

8

Answer 2

$\frac{x^{2}}{4}$+ $\frac{y^{2}}{16}$= 1

Ž $\left\lbrack \begin{matrix} a^{2} = 4 \\ b^{2} = 16 \end{matrix} \right.\$ \ a < b

Sum of focal distance

Ž PS + PS¢ = length of the major axis = 2(4) = 8