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Question

Mathematics Question on Binomial theorem

The sum of the coefficients of (6a5b)n(6\,a-5\,b)^n, where nn is a positive integer, is

A

11

B

1-1

C

2n2^n

D

2n12^n-1

Answer

11

Explanation

Solution

For the sum of the coefficients in the expansion of (6a5b)n(6 a-5 b)^{n}, put a=b=1a=b=1
\therefore Sum of the coefficients =(65)n=(6-5)^{n}
=1n=1=1^{n}=1