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Question: The sum of squares of deviations for \(10\) observations taken from mean \(50\) is \(250\). Then coe...

The sum of squares of deviations for 1010 observations taken from mean 5050 is 250250. Then coefficient of variation is
A) 10%10\%
B) 40%40\%
C) 50%50\%
D) None

Explanation

Solution

For solving this problem students need to find the standard deviation and coefficient of variation. Here it is given that the sum of squares of deviations for some observation taken from the mean value is given.

Formula used: Standard deviation (σ)\left( \sigma \right) =1nXiX2\sqrt {\dfrac{1}{n}\sum {{{\left| {{X_i} - \overline X } \right|}^2}} }
Co- efficient of variation = standard deviationmean\dfrac{{{\text{standard deviation}}}}{{{\text{mean}}}}×100100
That is, Coefficient of variation = σX×100\dfrac{\sigma }{{\overline X }} \times 100

Complete step-by-step solution:
Given that the sum of deviation for 1010 observation taken from mean 5050 is 250250.
Here n=1010, Mean (X)\left( {\overline X } \right)= 5050
And X1X2{\left| {{X_1} - \overline X } \right|^2}+X2X2{\left| {{X_2} - \overline X } \right|^2}+......+X9X2{\left| {{X_9} - \overline X } \right|^2}+X10X2{\left| {{X_{10}} - \overline X } \right|^2}=250250, whereX1{X_1} ,, X2{X_2}X10{X_{10}}be the 1010observations.
That is, i=110XiX2\sum\limits_{i = 1}^{10} {{{\left| {{X_i} - \overline X } \right|}^2}} =250250
We know that, σ=1nXiX2\sqrt {\dfrac{1}{n}\sum {{{\left| {{X_i} - \overline X } \right|}^2}} }
Substitute the given values, we get
\Rightarrowσ=110×250\sqrt {\dfrac{1}{{10}} \times 250}
\Rightarrowσ=25\sqrt {25}
Taking square root, we get
\Rightarrowσ=55
Therefore standard deviation (σ)\left( \sigma \right)= 55
Now students, our next aim is to find coefficient of variation
We know that, coefficient of variation = σX×100\dfrac{\sigma }{{\overline X }} \times 100
Now substitute σ = 55 and mean (X)\left( {\overline X } \right)=5050 in the formula of coefficient of variation.
\therefore Coefficient of variation = 550×100\dfrac{5}{{50}} \times 100
110×100\Rightarrow \dfrac{1}{{10}} \times 100
0.1×100\Rightarrow 0.1 \times 100
10%\Rightarrow 10\%

Therefore, Coefficient of variation = 10%10\%

Note: Standard deviation is the measure of dispersion of a set of data from its mean Standard Deviation is also known as root mean square deviation as it is the square root of means of the squared deviation from the arithmetic mean.
Students may get confused while working on Standard Deviation. So following steps will help students to find σ\sigma
Step 11: Find the mean.
Step 22: For each data point, find the square of its distance to the mean.
Step 33: Sum the values from step 22.
Step 44: Divide by the number of observations.
Step 55: Finally take square root.