Solveeit Logo

Question

Question: The sum of second term and the seventh term of an A.P. is 30. If its fifteenth term is 1 less than t...

The sum of second term and the seventh term of an A.P. is 30. If its fifteenth term is 1 less than twice its eighth term, find the A.P.

Explanation

Solution

We will first write the formula for nth{n^{th}} term of an A.P. Then apply the given condition which will help us form two different equations and we have two variables as well a and d. So, we can solve the equations for a and d and get the answer.

Complete step-by-step answer:
Let us first of all write the formula for nth{n^{th}} term of an A.P.
an=a+(n1)d\Rightarrow {a_n} = a + (n - 1)d, where a is the first term of the A.P, d is the common difference and an{a_n} is the nth{n^{th}} term of A.P.
We are given that: sum of second term and the seventh term of an A.P. is 30.
We can write this as:- a2+a7=30{a_2} + {a_7} = 30.
Applying the formula for an{a_n} that is an=a+(n1)d{a_n} = a + (n - 1)d in a2{a_2} and a7{a_7}. So, we will have:-
(a+d)+(a+6d)=30\Rightarrow (a + d) + (a + 6d) = 30
Simplifying this by combining the like terms, we will get:-
2a+7d=30\Rightarrow 2a + 7d = 30 …………….(1)
We also are given that: fifteenth term is 1 less than twice its eighth term.
We can rewrite it as: a15=2a81{a_{15}} = 2{a_8} - 1.
Applying the formula for an{a_n} that is an=a+(n1)d{a_n} = a + (n - 1)d in a8{a_8} and a15{a_{15}}. So, we will have:-
a+14d=2(a+7d)1\Rightarrow a + 14d = 2(a + 7d) - 1
Simplifying this by opening the brackets, we will get:-
a+14d=2a+14d1\Rightarrow a + 14d = 2a + 14d - 1
Simplifying it by clubbing the like terms, we will get:-
a=1\Rightarrow - a = - 1
Multiplying by -1 on both the sides, we will get:-
a=1\Rightarrow a = 1.
Hence, the first term of the A.P. is 1.
Putting this value of a in (1), we will get:-
2+7d=30\Rightarrow 2 + 7d = 30
Taking the 2 from LHS to RHS, we will get:-
7d=28\Rightarrow 7d = 28
Taking the 7 from LHS to RHS, we will get:-
d=287=4\Rightarrow d = \dfrac{{28}}{7} = 4
Hence, the common difference is 4.
Since an AP is given by a, a + d, a + 2d, a + 3d, a + 4d, ………..
Hence, the A.P. will be:- 1, 5, 9, 13, 17 ……..

Note: The students must remember that they need to have as much equation as the number of unknown variables to find their value.
Fun Fact:- If a, b, c are in AP, then 2b = a + c.
If each term of an AP is increased, decreased, multiplied, or divided by a constant non-zero number, then the resulting sequence is also in AP.