The sum of odd integralegers from (1) to (2001) is | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

The sum of odd integers from $1$ to $2001$ is

A

$(1121)^2$

B

$(1101)^2$

C

$(1001)^2$

D

$(1021)^2$

Answer

$(1001)^2$

Explanation

Solution

$1+3+5+\ldots+2001$ Sum of odd integers $=n^{2}=(1001)^{2}$