Question

The sum of numbers from 250 to 1000 which are divisible by 3 is.

• A. 135657
• B. 136557
• C. 161575
• D. 156375

Answer 1

Answer: (D)

156375

Answer 2

The number divisible by 3 between 250 to 1000 are 252, 255, .........., 999.

$\therefore$ $T _ { n } = 999 = 252 + ( n - 1 ) 3$ $\Rightarrow$ $333 = 84 + n - 1$

$\Rightarrow$ $n = 250$

$\therefore$ $S = \frac { n } { 2 } [ a + l ] = \frac { 250 } { 2 } [ 252 + 999 ]$ =$125 \times 1251 = 156375$.