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Question

Question: The sum of \(n\)terms of the sequence \(\log a,\log ar,\log a{r^2},...\) is: A.\(\dfrac{n}{2}\log ...

The sum of nnterms of the sequence loga,logar,logar2,...\log a,\log ar,\log a{r^2},... is:
A.n2loga2rn1\dfrac{n}{2}\log {a^2}{r^{n - 1}}
B.nloga2rn1n\log {a^2}{r^{n - 1}}
C.3n2loga2rn1\dfrac{{3n}}{2}\log {a^2}{r^{n - 1}}
D.None of these

Explanation

Solution

Hint: We first simplify the given sequence and then find its first term and common difference. To find the sum of nnterms of the given sequence, use the formula , Sn=n2(2a+(n1)d){S_n} = \dfrac{n}{2}\left( {2a + \left( {n - 1} \right)d} \right). To get the final answer, use the properties of log to simplify the answer.

Complete step by step answer:

The first term of the sequence is loga\log a
We will first simplify the given sequence.
We know that, log(xy)=logx+logy\log \left( {xy} \right) = \log x + \log y
Therefore, we write the given sequence as, loga,loga+logr,loga+logr2,...\log a,\log a + \log r,\log a + \log {r^2},...
Also, log(xm)=mlogx\log \left( {{x^m}} \right) = m\log x
Hence, we have, loga,loga+logr,loga+2logr,...\log a,\log a + \log r,\log a + 2\log r,...
Now, we can observe that the given sequence is an AP as logr\log r is added to each term.
Now, we will find the common difference by subtracting the second tern from the first one.
Hence, we get common difference dd as,
d=loga+logrloga d=logr  d = \log a + \log r - \log a \\\ d = \log r \\\
We have to find the sum of nnterms of the given sequence.
We know that the sum of nn terms of a sequence is n2(2a+(n1)d)\dfrac{n}{2}\left( {2a + \left( {n - 1} \right)d} \right), where aa is the first term and dd is the common difference.
Substitute the values of the first term and the common difference to find the sum of nnterms of the sequence.
Hence, sum of nn terms is
n2(2(loga)+(n1)logr)\dfrac{n}{2}\left( {2\left( {\log a} \right) + \left( {n - 1} \right)\log r} \right)
We can simplify the above expression using the properties of log, log(xm)=mlogx\log \left( {{x^m}} \right) = m\log x
\Rightarrow n2(loga2+logrn1)\dfrac{n}{2}\left( {\log {a^2} + \log {r^{n - 1}}} \right)
Hence, option A is correct.

Note: We have to use properties of log to simplify the given sequence such as, log(xy)=logx+logy\log \left( {xy} \right) = \log x + \log y and log(xm)=mlogx\log \left( {{x^m}} \right) = m\log x. Many students make mistakes by considering the given sequence as GP. It is after applying the properties of log, we will observe that the given sequence is an AP.