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Question: The sum of infinite series :\(\frac { 1 } { ( 1 + a ) ( 2 + a ) }\) + \(\frac { 1 } { ( 2 + a ) ( 3 ...

The sum of infinite series :1(1+a)(2+a)\frac { 1 } { ( 1 + a ) ( 2 + a ) } + 1(2+a)(3+a)\frac { 1 } { ( 2 + a ) ( 3 + a ) }

+ 1(3+a)(4+a)\frac { 1 } { ( 3 + a ) ( 4 + a ) }…¥ where a is a constant is –

A
B
C

¥

D

None

Answer
Explanation

Solution

S = + (12+a−13+a)\left( \frac { 1 } { 2 + a } - \frac { 1 } { 3 + a } \right)+

……. =