Question
Question: The sum of first n terms of an arithmetic sequence is \(5{n^2} + 2n\) . (a) What is the sum of the...
The sum of first n terms of an arithmetic sequence is 5n2+2n .
(a) What is the sum of the first two terms of this sequence ?
(b) Write the first two terms of the sequence .
Solution
As in the sum of first n terms of an arithmetic sequence is 5n2+2n so in part (a) put n=2 then we get sum first two term in part (b) we know that the sum of the one term is the term itself hence if we put n=1 in the equation we get first term for second term use an=Sn+1−Sn .
Complete step-by-step answer:
At in the given question it is given that the sum of first n terms of an arithmetic sequence is 5n2+2n where n is the number of the term up to which we have to find the sum .
So in the part (a) we have to find the sum of first two term for this we have to do is ,
Put n=2 so that we get the sum of first two term
Hence on putting n=2 in the equation 5n2+2n
5(2)2+2(2)
on solving 5×4+4 = 24
Hence the sum of first two term is 24
Now in the part (b) we have to find out the first two term of the sequence
we know that the sum of the one term is the term itself hence if we put n=1 in the equation 5n2+2n we get the first term,
a1=5(1)+2×1
⇒ a1=7
So the first term is 7
As for the second term use formula an=Sn+1−Sn but this is not valid for n=1 where
Sn = 5n2+2n
⇒ a2=S3−S2 now put n=3 and n=2 in the equation 5n2+2n
⇒ a2=5(3)2+2(3)−5(2)2−2(2)
On solving ,
⇒ a2=45+6−20−4 = 27
Hence the second term is 27.
Note: As in the question we can also find the sequence equation in the form of term we know that the an=Sn+1−Sn ( n=1 ) and Sn = 5n2+2n So on putting
an=5(n+1)2+2(n+1)−5n2−2n ,
2n is cancel out , an=5(n+1)2+2−5n2 on solving further an=5(n2+2n+1)+2−5n2
an=10n+7 but not valid for n=1