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Question

Mathematics Question on Natural Number

The sum of first 'n' natural numbers is

A

Σn=n(n−1)2Σn=\frac {n(n-1)}{2}

B

Σn=n(n+1)2Σn=\frac {n(n+1)}{2}

C

Σn=n(1−n)2Σn=\frac {n(1-n)}{2}

D

Σn=n2(n+1)22Σn=\frac {n^2(n+1)^2}{2}

Answer

Σn=n(n+1)2Σn=\frac {n(n+1)}{2}

Explanation

Solution

The correct option is (B):

Σn=n(n+1)2Σn=\frac {n(n+1)}{2}

.