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Question

Mathematics Question on Geometric Progression

The sum of first 10 terms of a G.P. is equal to 244 times the sum of first five terms. Then the common ratio is

A

7

B

3

C

4

D

5

Answer

3

Explanation

Solution

S10=244S_{10} = 244 S5a(1r10)1r=244a(1r5)1rS_{5}\Rightarrow \frac{a\left(1-r^{10}\right)}{1-r} = 244 a\frac{\left(1-r^{5}\right)}{1-r} 1r10=244(1r5)\Rightarrow 1-r^{10} = 244 \left(1-r^{5}\right) (1r5)(1+r5)=244(1r5) \Rightarrow \left(1-r^{5}\right)\left(1+r^{5}\right) = 244\left(1-r^{5}\right) 1+r5=244 \Rightarrow 1+r^{5}= 244 r5=243=(3)5\Rightarrow r^{5} = 243 = \left(3\right)^{5} r=3\Rightarrow r=3