Question
Question: The sum of binomial coefficient in the expansion of \[{\left( {x + \dfrac{1}{x}} \right)^n}\] is 64,...
The sum of binomial coefficient in the expansion of (x+x1)n is 64, the term independent of x is equal to
A) 10
B) 20
C) 40
D) 60
Explanation
Solution
Since the given sum uses a binomial expansion we will find the sum of its binomial coefficients and then the term independent of x.
Complete step-by-step answer:
Using binomial theorem,
(x+a)n=nC0xn+nC1xn−1a+nC2xn−2a2+.......nCnan
Here the binomial coefficients are nC0, nC1, nC2…….
Sum of these binomial coefficients is =∑r=0nnCr=2n
Now the term independent of x is ,
Tr+1=nCr(x)n−r(x1)r
⇒Tr+1=6Cr(x)6−r(x1)r
Since the term is independent of x,
6−2r=0 6=2r r=3Since r=3 then term independent of x will be,
⇒T3+1=6C3 ⇒T4=3!(6−3)!6! ⇒T4=3!3!6! ⇒T4=3×2×16×5×4 ⇒T4=20So option B is the correct answer.
Additional information:
If n is any positive integer, then