Question

The sum of all two digit numbers which, when divided by 4, yield unity as a remainder is.

• A. 1190
• B. 1197
• C. 1210
• D. None of these

Answer 1

Answer: (C)

1210

Answer 2

The given numbers are 13, 17, ..... 97. This is an AP with first term 13 and common difference 4. Let the number of terms be $n$.

Then $97 = 13 + ( n - 1 ) 4$ $\Rightarrow$ $4 n = 88$ $\Rightarrow$ $n = 22$

Therefore the sum of the numbers

$= \frac { 22 } { 2 } [ 13 + 97 ] = 11 ( 110 ) = 1210$.