Question

The sum of all two digit numbers which when divided by 4, yield unity as remainder is –

• A. 1012
• B. 1201
• C. 1212
• D. 1210

Answer 1

Answer: (D)

1210

Answer 2

S = 13+17+21+.......+ 97 Here n = $\frac { 97 - 13 } { 4 }$ +1 = 22

So, S₂₂ = $\frac { 22 } { 2 }$(13 + 97) = 1210