Question

The sum of all two digit natural number which divided by '4' yield remainder is 1, is-

• A. 1200
• B. 1210
• C. 1300
• D. None of these

Answer 1

Answer: (B)

1210

Answer 2

Required sum is 13 + 17 + 21 + …. + 97

Let number of terms are 'n'

97 = 13 + (n –1) 4

$\frac{84}{4}$= (n –1) ̃ n = 22

required sum = $\frac{22}{2}$ (13 + 97) = 11 × 110 = 1210