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Question

Question: The sum of all positive integral divisors of 1800 is...

The sum of all positive integral divisors of 1800 is

A

15x13x124

B

15x26x31

C

15x26x124

D

15x13x31

Answer

15x13x31

Explanation

Solution

Since 1800 = 23 x 32 x 52

Sum of divisors = (24121)6mu(33131)6mu(53151)\left( \frac{2^{4} - 1}{2 - 1} \right)\mspace{6mu}\left( \frac{3^{3} - 1}{3 - 1} \right)\mspace{6mu}\left( \frac{5^{3} - 1}{5 - 1} \right)

= 15 x 13 x 31