Solveeit Logo

Question

Mathematics Question on Application of derivatives

The subtangent at x=π/2x = \pi/2 on the curve y=xsinxy = x \sin x is

A

0

B

1

C

π/2\pi/2

D

none of these

Answer

π/2\pi/2

Explanation

Solution

y=xsinxy=x\,sin\,x
dydx=xcosx+sinx1=xcosx+sinx\Rightarrow \frac{dy}{dx}=x\,cos\,x+sin\,x\cdot1=x\,cos\,x+sin\,x
At x=π2,dydx=0+sinπ2=1x=\frac{\pi}{2}, \frac{dy}{dx}=0+sin \frac{\pi}{2}=1
and y=π2sinπ2=π2y=\frac{\pi}{2} sin \frac{\pi}{2} =\frac{\pi}{2}
Now subtangent =yy1atx=π/2=π/21=π2=\left|\frac{y}{y_{1}}\right|_{at\,x=\pi/2}=\frac{\pi/2}{1}=\frac{\pi}{2}