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Question: The substance undergoes first order decomposition. The decomposition follows two parallel first orde...

The substance undergoes first order decomposition. The decomposition follows two parallel first order reactions as :

K1 = 1.26 × 10-4 sec-1 and K2 = 3.8 × 10-5 sec-1K_{1}\text{ = 1.26 }\text{×}\text{ 1}\text{0}^{\text{-4}}\text{ se}\text{c}^{\text{-1}}\text{ and }\text{K}_{2}\text{ = 3.8 }\text{×}\text{ 1}\text{0}^{\text{-5}}\text{ se}\text{c}^{\text{-1}}

The percentage distribution of B and C

A

80% B and 20% C

B

76.83% B and 23.17%C

C

90% B and 10% C

D

60% B and 40% C

Answer

76.83% B and 23.17%C

Explanation

Solution

%ofB=k1×100k1+k2=1.26×104×10012.6×105+3.8×105=76.83%.\% ofB = \frac{k_{1} \times 100}{k_{1} + k_{2}} = \frac{1.26 \times 10^{- 4} \times 100}{12.6 \times 10^{- 5} + 3.8 \times 10^{- 5}} = 76.83\%.

%ofC=k2×100k1+k2=3.8×105×10012.6×105+3.8×105=23.17%\% ofC = \frac{k_{2} \times 100}{k_{1} + k_{2}} = \frac{3.8 \times 10^{- 5} \times 100}{12.6 \times 10^{- 5} + 3.8 \times 10^{- 5}} = 23.17\%