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Question: The Sturges rule for determining the number of classes \(\left( n \right)\) in a frequency distribut...

The Sturges rule for determining the number of classes (n)\left( n \right) in a frequency distribution with total frequency NN is
(A) n=1+2.3108Nn = 1 + 2.3108\,N
(B) N=1+3.3108NN = 1 + 3.3108\,N
(C) n=1+3.3logNn = 1 + 3.3\log \,N
(D) n=13.3logNn = 1 - 3.3\log \,N

Explanation

Solution

In this question we just have to recall the formula of Sturges rule and then we will put the value of number of classes , the value of total frequency in the Sturges rule. The Sturges rule is used to determine the number of classes when the total number of observations is given.

Formula used: Sturges rule to find the number of classes is given by K=1+3.322logNK = 1 + 3.322\log \,N where KK is the number of classes and NN is the total frequency.

Complete step-by-step solution:
The number of classes given in the question is nn and total frequency is NN
We know that Sturges rule is used to find the number of classes which is used in a histogram or frequency distribution.
From Sturges rule we can write.
K=1+3.322logNK = 1 + 3.322\log \,N
Put the values of number of classes and total frequency in the above equation. Therefore, we will get
n=1+3.322logNn = 1 + 3.322\log \,N
We can write the above equation as n=1+3.3logNn = 1 + 3.3\log \,N .

Hence, the correct option is (C).

Additional information: we will see in this example how to apply Sturges rule. Example: If the total number of observations are 10001000 then we can find the number of classes by the Sturges rule K=1+3.322logNK = 1 + 3.322\log \,N
K=1+3.322log1000 K=1+3.322(3)=10.966 \Rightarrow K = 1 + 3.322\log 1000 \\\ \Rightarrow K = 1 + 3.322\left( 3 \right) = 10.966

Note: The important thing in this question is the rule given by Sturges which we have to remember. The Sturges rule is the function of log\log so while solving the question related to Sturges rule just make sure that we are comfortable with the properties of log\log .