Question

The structure of phenacetin is:
A.
B.
C.
D.

Answer 1

We know that to answer this you should know that phenacetin belongs to the class of acetamide. It is prepared by Williamson’s ether synthesis and thus is a derivative of ether too. We can write its general formula as ${{C}_{10}}{{H}_{13}}N{{O}_{2}}$ . You can use this to determine its structure.

Complete step by step answer:
To answer this, firstly let us discuss the structure of phenacetin. Phenacetin is a derivative of acetamide and an ether. It can be derived from Williamson’s ether synthesis reaction. It can be derived from N-phenylacetamide, $4-$ethoxyaniline and paracetamol. It is used as an analgesic. It is a painkiller and it is the world's synthetic pharmaceutical drug. Its effects are due to its actions on the sensory tract of the spinal cord. Now, let us see its structure. It is an organic compound and it belongs to the class of acetamide. An acetamide is an amide derivation of acetic acid. In phenacetin, one hydrogen atom of the group is substituted by a $4\text{ }$ethoxy phenyl group. We can draw its structure as: Phenacetin is N-($4-$Ethoxyphenyl)acetamide.

Therefore, the correct answer is option C.

Note:
Remember that the williamson’s ether synthesis, an alkoxide anion undergoes substitution nucleophilic bimolecular reaction with an alkyl halide and forms ether. We generally carry out this reaction for the formation of unsymmetrical ethers.