Question

The straight lines $a + b + c = 0$,

will be concurrent, if point is

• A. (4, 3)
• B. $\left( \frac { 1 } { 4 } , \frac { 1 } { 3 } \right)$
• C. $\left( \frac { 1 } { 2 } , \frac { 1 } { 3 } \right)$
• D. None of these

Answer 1

Answer: (B)

$\left( \frac { 1 } { 4 } , \frac { 1 } { 3 } \right)$

Answer 2

The set of lines is $a + b + c = 0$

Eliminating c, we get $4 a x + 3 b y - ( a + b ) = 0$

⇒ $a ( 4 x - 1 ) + b ( 3 y - 1 ) = 0$

They pass through the intersection of the lines $\left( \frac { 1 } { 4 } , \frac { 1 } { 3 } \right)$