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Question: The straight lines I<sub>1</sub>, I<sub>2</sub>, I<sub>3</sub> are parallel and lie in the same plan...

The straight lines I1, I2, I3 are parallel and lie in the same plane. A total number of m points are taken on I1 ; n points on I2 , k points on I3. The maximum number of triangles formed with vertices at these points are –

A

m + n + kC3

B

m + n +kC3mC3nC3kC3

C

mC3 + nC3 + kC3

D

None of these

Answer

m + n +kC3mC3nC3kC3

Explanation

Solution

Total number of points = m +n + k. Therefore the total number of triangles formed by these points is m + n + kC3. But out of these m + n + k points, m points lie on I1, n points lie on I2 and k points lie on I3 and by joining three points on the same line we do not obtain a triangle. Hence the total number of triangles is m + n + kC3mC3nC3kC3.