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Question: The straight line passing through the point of intersection of the straight lines \( x - 3y + 1 = 0 ...

The straight line passing through the point of intersection of the straight lines x3y+1=0x - 3y + 1 = 0 and 2x+5y9=02x + 5y - 9 = 0 and having infinite slope and at a distance of 22 units from the origin, has the equation
(1) x=2x = 2
(2) 3x+y1=03x + y - 1 = 0
(3) y=1y = 1
(4) None of these

Explanation

Solution

Hint : A straight line is an endless one dimensional figure that has no width. The straight line is a combination of endless points joined on both sides of a point. A straight line does not have any curve in it. The straight line can be horizontal, vertical or slanted. When two or more straight lines cross each other in a plane, they are called intersecting lines.

Complete step-by-step answer :
First we find the intersection point of the straight lines
Take x3y+1=0x - 3y + 1 = 0 ……………………………..(1)
2x+5y9=02x + 5y - 9 = 0 …………………………………..(2)
From equation (1) , we get
x=3y1x = 3y - 1 ………………………………(3)
Use equation (3) in equation (2) , we get
2(3y1)+5y9=02(3y - 1) + 5y - 9 = 0
Multiplying and we get
6y2+5y9=0\Rightarrow 6y - 2 + 5y - 9 = 0
11y11=0\Rightarrow 11y - 11 = 0
11y=11\Rightarrow 11y = 11
We divide both sides by 1111 , we get
11y11=1111\Rightarrow \dfrac{{11y}}{{11}} = \dfrac{{11}}{{11}}
y=1\Rightarrow y = 1
Put the value of y=1y = 1 in equation (3) , we get
x=3×11x = 3 \times 1 - 1
x=31\Rightarrow x = 3 - 1
x=2\Rightarrow x = 2
Therefore the intersection point is (2,1)(2,1) .
From the given data we have infinite slope , means θ=π2\theta = \dfrac{\pi }{2}
Therefore the straight line parallel to Y-axis i.e., x=ax = a , where aa is the distance from origin.
And also given that the distance from origin is 22 units.
Then we have the straight line x=2x = 2 .
Therefore the option (1) is correct.
So, the correct answer is “Option 1”.

Note : The slope of a line is a number measured as its “steepness”, usually denoted by the letter mm . It is the change in yy for a unit change in xx for a change in xx along the line. The formula of slope of a straight line is m=tanθm = \tan \theta , where θ\theta is the angle between the X-axis and the straight line.