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Question: The straight line joining any point P on the parabola y<sup>2</sup> = 4ax to the vertex and perpen...

The straight line joining any point P on the parabola
y2 = 4ax to the vertex and perpendicular from the focus to the tangent at P, intersect at R, then the equation of the locus of R is-

A

2x2 + y2 – 2ay = 0

B

2x2 + y2 – 2ax = 0

C

2x2 + 2y2 –ay = 0

D

x2 + 2y2 –ax = 0

Answer

2x2 + y2 – 2ax = 0

Explanation

Solution

P º (at2, 2at), OP º y = 2t\frac{2}{t}x

Equation of tangent at P ty = x + at2

R (h, k) lies on both k = 2t\frac{2}{t}h ̃ t = 2hk\frac{2h}{k}

2hk\frac{h}{k}. k = h + a (2hk)2\left( \frac{2h}{k} \right)^{2}

Locus ̃ 2x2 + y2 –2ax = 0