test","extracted_subject":"PHYSICS","extracted_chapter":"DUAL NATURE OF RADIATION AND MATTER","extracted_topic":"WAVE NATURE OF MATTER","questionPreviewUrl":"https://cdn.pureessence.tech/question-previews/packed_canvases/canvas_795.png?top_left_x=1064&top_left_y=498&width=532&height=291&app=solveeit"},"seo_metadata":{"keywords":[]},"doubt_solver_data":{"concept_summary":[]},"embeddings":[],"is_hidden":false,"_id":"66d23c9570136192204bfe3f","slug":"the-stopping-potential-vsub0sub-versus-frequency-n","content":"The stopping potential (V₀) versus frequency (n) plot of a substance is shown in figure, the threshold wavelength is –\n\n![](https://cdn.pureessence.tech/canvas_629.png?top_left_x=0&top_left_y=0&width=291&height=300)","options":[{"_id":"68a44c277f15af4716cb98d3","text":"5 × 10¹⁴ m","sequence":0,"isCorrect":false},{"_id":"68a44c277f15af4716cb98d4","text":"6000 Å","sequence":1,"isCorrect":true},{"_id":"68a44c277f15af4716cb98d5","text":"5000 Å","sequence":2,"isCorrect":false},{"_id":"68a44c277f15af4716cb98d6","text":"Cannot be estimated from given data","sequence":3,"isCorrect":false}],"correct_answer":"6000 Å","explanation":"n₀ = 5 × 10¹⁴ Hz\n\nl₀ = \\(\\frac { \\mathrm { c } } { v _ { 0 } }\\) = \\(\\frac { 3 \\times 10 ^ { 8 } } { 5 \\times 10 ^ { 14 } }\\) m\n\n= 6 × 10^–7 m\n\n= 6000 Å","question_type":"single_choice","appeared_in":[],"created_at":"2024-08-30T21:41:41.875Z","__v":0,"vector_store_id":"f721ecb9-72f1-4e36-b003-7a30e4967485","updated_at":"2024-08-30T21:41:41.875Z","isStarred":false},"params":{"questionSlug":"the-stopping-potential-vsub0sub-versus-frequency-n"}}]}]]

Question: The stopping potential (V<sub>0</sub>) versus frequency (n) plot of a substance is shown in figure, ...

Solution