Solveeit Logo

Question

Question: The stopping potential for the photoelectron emitted from a mental surface of work function \(1.7\;e...

The stopping potential for the photoelectron emitted from a mental surface of work function 1.7  eV1.7\;eV is 10.4  eV10.4\;eV. Identify the energy levels corresponding to the transition in hydrogen atom which will result in emission of wavelength equal to that of incident radiation for the atom photoelectric effect.

Explanation

Solution

We know that photoelectric effect is the process observed when the incident radiation of light having energy more than the threshold energy or the work function is incident surface, emits charged particles, called the photons. Using the formula of photoelectric effect we can solve the following questions.

Complete step-by-step solution:
We know from the dual nature of light, that it is both wave and also contains particles or photons. Photoelectric electric effect is a foundation to prove that light has particle nature. As defined above, it was found that light particles are nothing but species called photons. From Planck’s equation, we know the energy EE of light as a wave can be expressed as
E=hv=hcλE=hv=\dfrac{hc}{\lambda}, where hh is Planck's constant and vv denotes the frequency of light waves with speed cc and wavelength λ\lambda.
Thus, here in photoelectric effect , when a light with some energy is incident on a metal, the energy of the light EpE_p wave gets distributed as the energy of the electron EeE_e and the threshold or the work energy of the metal ϕ\phi, and can be expressed as
Ep=Ee+ϕE_p=E_e+\phi
Here, given that ϕ=10.4ev\phi=10.4ev and Ee=1.7evE_e=1.7ev
Then the energy of the photon Ep=10.4+1.7=12.1eVE_p= 10.4+1.7=12.1eV

Consider the energy level of hydrogen atom as shown below

The energy levels, which corresponds to EpE_p is from n=3n=3 to n=1n=1 as E3E1=1.51+13.6=12.1eVE_3-E_1=-1.51+13.6=12.1eV

Note: Here, we must first calculate the energy of a photon, by photoelectric effect, and then compare the energy obtained to find the energy level of hydrogen. Here, it is important to note that the photon is nothing but the hydrogen atom which is undergoing excitation; hence we must compare the energy of the photon to the difference of the energy levels of the hydrogen.