Question

The steady state current in the circuit shown below is :

• A. 0.67 A
• B. 1.5 A
• C. 2 A
• D. 1 A

Answer 1

Answer: (C)

2 A

Answer 2

In steady state, the capacitor acts as an open circuit (infinite resistance). Therefore, the 5 $\Omega$ resistor is not part of the circuit. The circuit simplifies to:

The total resistance is 2 $\Omega$ + 3 $\Omega$ = 5 $\Omega$. Using Ohm's law, I = V/R = $\frac{10 \, V}{5 \, \Omega} = 2 \, A$